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Physics · 2019
JEE Main · 11 January 2019, Shift 1 · Q3
A body is projected at t =0 with a velocity 10 ms^-1 at an angle of 60° with the horizontal. The radius of curvature of its trajectory at t =1 s is…
A body is projected at $\displaystyle \mathrm{t}=0$ with a velocity $\displaystyle 10 \mathrm{~ms}^{-1}$ at an angle of $\displaystyle 60$° with the horizontal. The radius of curvature of its trajectory at $\displaystyle \mathrm{t}=1 \mathrm{~s}$ is R. Neglecting air resistance and taking acceleration due to gravity $\displaystyle \mathrm{g}=10 \mathrm{~ms}^{-2}$, the value of R is :
Official answer
(3)
2.$\displaystyle 8$ m
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.