Physics · 2020
JEE Main · 5 September 2020, Shift 1 · Q25
A beam of electrons of energy E scatters from a target having atomic spacing of 1. The first maximum intensity occurs at θ=60^°. Then E (in eV) is \…
A beam of electrons of energy E scatters from a target having atomic spacing of $\displaystyle 1 \AA$. The first maximum intensity occurs at $\displaystyle \theta=60^{\circ}$. Then E (in eV) is \_\_\_\_. (Planck constant $\displaystyle \mathrm{h}=6.64 \times 10^{-34} \mathrm{Js}$,
$$1 \mathrm{eV}=1.6 \times 10^{-19} \mathrm{~J},
$$
electron mass $\displaystyle m=9.1 \times 10^{-31} \mathrm{~kg}$ )
Official answer
50.5 ± 0.5
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JEE Main 2020 Physics question, with the answer from NTA’s final answer key. Where our answers come from.