Physics · 2022
JEE Main · 28 July 2022, Shift 2 · Q21
A ball is thrown vertically upwards with a velocity of 19.6 ms^-1 from the top of a tower. The ball strikes the ground after 6 s. The height from the…
A ball is thrown vertically upwards with a velocity of $\displaystyle 19.6 \mathrm{~ms}^{-1}$ from the top of a tower. The ball strikes the ground after $\displaystyle 6$ s . The height from the ground up to which the ball can rise will be $\displaystyle \left(\frac{k}{5}\right) \mathrm{m}$. The value of k is \_\_\_\_ (use $\displaystyle \mathrm{g}=9.8 \mathrm{~m} / \mathrm{s}^2$ )
Official answer
392
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JEE Main 2022 Physics question, with the answer from NTA’s final answer key. Where our answers come from.