Physics · 2022
JEE Main · 28 June 2022, Shift 2 · Q32
A ball is spun with angular acceleration α=6 t^2-2 t where t is in second and α is in rads ^-2. At t =0, the ball has angular velocity of 10 rads^-1…
A ball is spun with angular acceleration $\displaystyle \alpha=6 \mathrm{t}^2-2 \mathrm{t}$ where t is in second and $\displaystyle \alpha$ is in rads $\displaystyle { }^{-2}$. At $\displaystyle \mathrm{t}=0$, the ball has angular velocity of $\displaystyle 10 \mathrm{rads}^{-1}$ and angular position of $\displaystyle 4$ rad. The most appropriate expression for the angular position of the ball is :
Official answer
(2)
$\displaystyle \frac{t^4}{2}-\frac{t^3}{3}+10 t+4$
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JEE Main 2022 Physics question, with the answer from NTA’s final answer key. Where our answers come from.