Physics · 2020
JEE Main · 7 January 2020, Shift 1 · Q3
A 60 HP electric motor lifts an elevator having a maximum total load capacity of 2000 kg. If the frictional force on the elevator is 4000 N, the…
A $\displaystyle 60$ HP electric motor lifts an elevator having a maximum total load capacity of $\displaystyle 2000$ kg. If the frictional force on the elevator is $\displaystyle 4000$ N , the speed of the elevator at full load is close to : $\displaystyle (1 \mathrm{HP}=746 \mathrm{~W}$, $\displaystyle \mathrm{g}=10 \mathrm{~ms}^{-2}$ )
Official answer
(2)
$\displaystyle 1.9 \mathrm{~ms}^{-1}$
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JEE Main 2020 Physics question, with the answer from NTA’s final answer key. Where our answers come from.