10 kg of ice at -10^° C is added to 100 kg of water to lower its temperature from 25 ^° C. Consider no heat exchange to surroundings. The decrement…

$\displaystyle 10$ kg of ice at $\displaystyle -10^{\circ} \mathrm{C}$ is added to $\displaystyle 100$ kg of water to lower its temperature from $\displaystyle 25$ $\displaystyle { }^{\circ} \mathrm{C}$. Consider no heat exchange to surroundings. The decrement to the temperature of water is $\displaystyle \_\_\_\_$ °C. (specific heat of ice $\displaystyle =2100 \mathrm{~J} / \mathrm{Kg} .{ }^{\circ} \mathrm{C}$, specific heat of water $\displaystyle =4200 \mathrm{~J} / \mathrm{Kg} .{ }^{\circ} \mathrm{C}$, latent heat of fusion of ice $\displaystyle =3.36 \times 10^5 \mathrm{~J} / \mathrm{Kg}$ )