Mathematics · 2022
JEE Main · 27 July 2022, Shift 2 · Q9
∫_0^2(|2 x^2-3 x|+[x-1/2]) d x, where [ t ] is the greatest integer function, is equal to:
$\displaystyle \int_0^2\left(\left|2 x^2-3 x\right|+\left[x-\frac{1}{2}\right]\right) \mathrm{d} x$, where $\displaystyle [\mathrm{t}]$ is the greatest integer function, is equal to :
Official answer
(2)
$\displaystyle \frac{19}{12}$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.