Mathematics · 2021
JEE Main · 25 February 2021, Shift 1 · Q67
The value of the integral ∫ (sin θ · sin 2 θ( sin^6 θ+ sin^4 θ+ sin^2 θ) √(2 sin^4 θ+3 sin^2 θ+6))/(1- cos 2 θ) d θ is: (where c is a constant of…
The value of the integral
$$\int \frac{\sin \theta \cdot \sin 2 \theta\left(\sin ^6 \theta+\sin ^4 \theta+\sin ^2 \theta\right) \sqrt{2 \sin ^4 \theta+3 \sin ^2 \theta+6}}{1-\cos 2 \theta} \mathrm{~d} \theta \text { is : }
$$
(where c is a constant of integration)
Official answer
(4)
$\displaystyle \frac{1}{18}\left[11-18 \cos ^2 \theta+9 \cos ^4 \theta-2 \cos ^6 \theta\right]^{\frac{3}{2}}+\mathrm{c}$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.