Mathematics · 2023
JEE Main · 29 January 2023, Shift 2 · Q67
The value of the integral ∫_1^2((t^4+1)/(t^6+1)) d t is
The value of the integral $\displaystyle \int_1^2\left(\frac{t^4+1}{t^6+1}\right) d t$ is
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle \tan ^{-1} 2+\frac{1}{3} \tan ^{-1} 8-\frac{\pi}{3}$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.