Mathematics · 2022
JEE Main · 30 June 2022, Shift 1 · Q7
The value of 1+1/(1+2)+1/(1+2+3)+…+1/(1+2+3+…+11) is equal to:
The value of
$$1+\frac{1}{1+2}+\frac{1}{1+2+3}+\ldots+\frac{1}{1+2+3+\ldots+11}
$$
is equal to :
Official answer
(2)
$\displaystyle \frac{11}{6}$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.