Mathematics · 2020
JEE Main · 9 January 2020, Shift 1 · Q63
The value of ∫_0^2 π (x sin^8 x)/(sin^8 x+ cos^8 x) d x is equal to:
The value of $\displaystyle \int_0^{2 \pi} \frac{x \sin ^8 x}{\sin ^8 x+\cos ^8 x} \mathrm{~d} x$ is equal
to :
Official answer
(4)
$\displaystyle \pi^2$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.