Mathematics · 2022
JEE Main · 25 June 2022, Shift 1 · Q2
The value of ∫_0^π (e^cos x sin x)/((1+ cos^2 x)( e^cos x+ e^- cos x)) d x is equal to:
The value of $\displaystyle \int_0^\pi \frac{\mathrm{e}^{\cos x} \sin x}{\left(1+\cos ^2 x\right)\left(\mathrm{e}^{\cos x}+\mathrm{e}^{-\cos x}\right)} \mathrm{d} x$ is equal to :
Official answer
(3)
$\displaystyle \frac{\pi}{4}$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.