Mathematics · 2023
JEE Main · 13 April 2023, Shift 2 · Q10
The value of (e^-(π)/4+∫_0^((π)/4) e^-x tan^50 x d x)/(∫_0^((π)/4) e^-x( tan^49 x+ tan^51 x) d x) is
The value of $\displaystyle \frac{e^{-\frac{\pi}{4}}+\int_0^{\frac{\pi}{4}} e^{-x} \tan ^{50} x d x}{\int_0^{\frac{\pi}{4}} e^{-x}\left(\tan ^{49} x+\tan ^{51} x\right) d x}$ is
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 50$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.