Mathematics · 2021
JEE Main · 26 August 2021, Shift 1 · Q69
The value of ∫_-1 / √ 2^1 / √ 2 (((x+1)/(x-1))^2+((x-1)/(x+1))^2-2)^1 / 2 d x is:
The value of $\displaystyle \int_{-1 / \sqrt{2}}^{1 / \sqrt{2}}\left(\left(\frac{x+1}{x-1}\right)^2+\left(\frac{x-1}{x+1}\right)^2-2\right)^{1 / 2} \mathrm{~d} x$ is :
Official answer
(3)
$\displaystyle \log _{\mathrm{e}} 16$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.