SolveIt is under development
SolveItJEE Main
Mathematics · 2013

JEE Main · 25 April 2013, Shift 1 · Q87

The value of 1^2+3^2+5^2+… … … ….+25^2 is:

The value of $\displaystyle 1^2+3^2+5^2+\ldots \ldots \ldots \ldots .+25^2$ is :
ShareWhatsAppTelegram

More from Progressions

JEE Main 2013 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.