Mathematics · 2021
JEE Main · 25 July 2021, Shift 1 · Q81
The term independent of ' x ' in the expansion of ((x+1)/(x^2 / 3-x^1 / 3+1)-(x-1)/(x-x^1 / 2))^10, where x ≠ 0,1 is equal to \ \ \ \.
The term independent of ' $\displaystyle x$ ' in the expansion of $\displaystyle \left(\frac{x+1}{x^{2 / 3}-x^{1 / 3}+1}-\frac{x-1}{x-x^{1 / 2}}\right)^{10}$, where $\displaystyle x \neq 0,1$ is equal to \_\_\_\_.
Official answer
210
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.