Mathematics · 2019
JEE Main · 12 April 2019, Shift 2 · Q72
The tangents to the curve y=(x-2)^2-1 at its points of intersection with the line x-y=3, intersect at the point:
The tangents to the curve $\displaystyle y=(x-2)^2-1$ at its points of intersection with the line $\displaystyle x-y=3$, intersect at the point :
Official answer
(1)
$\displaystyle \left(\frac{5}{2},-1\right)$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.