Mathematics · 2014
JEE Main · 19 April 2014, Shift 1 · Q82
The tangent at an extremity (in the first quadrant) of latus rectum of the hyperbola x^2/4-y^2/5=1,meets x - axis and y - axis at A and B…
The tangent at an extremity (in the first quadrant) of latus rectum of the hyperbola $\displaystyle \frac{x^2}{4}-\frac{y^2}{5}=1$,meets $\displaystyle x$ - axis and $\displaystyle y$ - axis at A and B respectively. Then $\displaystyle (\mathrm{OA})^2-(\mathrm{OB})^2$, where O is the origin, equals :
Official answer
(1)
$\displaystyle -\frac{20}{9}$
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