Mathematics · 2019
JEE Main · 9 January 2019, Shift 1 · Q82
Let 0<θ<(π)/2. If the eccentricity of the hyperbola x^2/(cos^2 θ)-y^2/(sin^2 θ)=1 is greater than 2, then the length of its latus rectum lies in the…
Let $\displaystyle 0<\theta<\frac{\pi}{2}$. If the eccentricity of the
hyperbola $\displaystyle \frac{x^2}{\cos ^2 \theta}-\frac{y^2}{\sin ^2 \theta}=1$ is greater than $\displaystyle 2$ , then the length of its latus rectum lies in the interval :
Official answer
(4)
$\displaystyle (3, \infty)$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.