Mathematics · 2024
JEE Main · 31 January 2024, Shift 1 · Q5
The sum of the series 1/(1-3 · 1^2+1^4)+2/(1-3 · 2^2+2^4)+3/(1-3 · 3^2+3^4)+… up to 10 -terms is
The sum of the series $\displaystyle \frac{1}{1-3 \cdot 1^2+1^4}+\frac{2}{1-3 \cdot 2^2+2^4}+\frac{3}{1-3 \cdot 3^2+3^4}+\ldots$ up to $\displaystyle 10$ -terms is
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle -\frac{55}{109}$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.