Mathematics · 2019
JEE Main · 8 April 2019, Shift 1 · Q69
The sum of the series 2 ·^20 C_0+5 ·^20 C_1+8 ·^20 C_2+11 ·^20 C_3+…+ 62.^20 C_20 is equal to:
The sum of the series $\displaystyle 2 \cdot{ }^{20} \mathrm{C}_0+5 \cdot{ }^{20} \mathrm{C}_1+8 \cdot{ }^{20} \mathrm{C}_2+11 \cdot{ }^{20} \mathrm{C}_3+\ldots+$ $\displaystyle 62 .{ }^{20} \mathrm{C}_{20}$ is equal to :
Official answer
(2)
$\displaystyle 2^{25}$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.