Mathematics · 2022
JEE Main · 29 June 2022, Shift 2 · Q4
The sum of the infinite series 1+5/6+12/6^2+22/6^3+35/6^4+51/6^5+70/6^6+… is equal to:
The sum of the infinite series $\displaystyle 1+\frac{5}{6}+\frac{12}{6^2}+\frac{22}{6^3}+\frac{35}{6^4}+\frac{51}{6^5}+\frac{70}{6^6}+\ldots$ is equal to:
Official answer
(3)
$\displaystyle \frac{288}{125}$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.