Mathematics · 2021
JEE Main · 3 August 2021, Shift 1 · Q82
The sum of modulus of all non-real roots of the equation, (x^2+4 x+6)(2 x^2+8 x+14)=12 is equal to \ \ \ \.
The sum of modulus of all non-real roots of the equation, $\displaystyle \left(x^2+4 x+6\right)\left(2 x^2+8 x+14\right)=12$ is equal to \_\_\_\_.
Official answer
6
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.