Mathematics · 2021
JEE Main · 27 July 2021, Shift 1 · Q69
Let α, β be two roots of the equation x^2+(20)^(1/4) x+(5)^(1/2)=0. Then α^8+β^8 is equal to:
Let $\displaystyle \alpha, \beta$ be two roots of the equation $\displaystyle x^2+(20)^{\frac{1}{4}} x+(5)^{\frac{1}{2}}=0$. Then $\displaystyle \alpha^8+\beta^8$ is equal to:
Official answer
(3)
$\displaystyle 50$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.