Mathematics · 2019
JEE Main · 10 January 2019, Shift 1 · Q88
The sum of all values of θ ∈(0, (π)/2) satisfying sin^2 2 θ+ cos^4 2 θ=3/4 is:
The sum of all values of $\displaystyle \theta \in\left(0, \frac{\pi}{2}\right)$ satisfying
$\displaystyle \sin ^2 2 \theta+\cos ^4 2 \theta=\frac{3}{4}$ is :
Official answer
(2)
$\displaystyle \frac{\pi}{2}$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.