Mathematics · 2022
JEE Main · 24 June 2022, Shift 2 · Q2
The sum of all the real roots of the equation (e^2 x-4)(6 e^2 x-5 e^x+1)=0 is
The sum of all the real roots of the equation $\displaystyle \left(e^{2 x}-4\right)\left(6 e^{2 x}-5 e^x+1\right)=0$ is
Official answer
(2)
$\displaystyle -\log _e 3$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.