Mathematics · 2021
JEE Main · 31 August 2021, Shift 1 · Q66
The sum of 10 terms of the series 3/(1^2 × 2^2)+5/(2^2 × 3^2)+7/(3^2 × 4^2)+… is:
The sum of $\displaystyle 10$ terms of the series $\displaystyle \frac{3}{1^2 \times 2^2}+\frac{5}{2^2 \times 3^2}+\frac{7}{3^2 \times 4^2}+\ldots$ is :
Official answer
(3)
$\displaystyle \frac{120}{121}$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.