Mathematics · 2023
JEE Main · 1 February 2023, Shift 2 · Q67
The sum Σ_n=1^∞ (2 n^2+3 n+4)/((2 n)!) is equal to:
The sum $\displaystyle \sum_{n=1}^{\infty} \frac{2 n^2+3 n+4}{(2 n)!}$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle \frac{13 e}{4}+\frac{5}{4 e}-4$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.