Mathematics · 2019
JEE Main · 10 April 2019, Shift 2 · Q67
The smallest natural number n, such that the coefficient of x in the expansion of (x^2+1/x^3)^n is ^n C_23, is:
The smallest natural number n , such that the coefficient of $\displaystyle x$ in the expansion of $\displaystyle \left(x^2+\frac{1}{x^3}\right)^{\mathrm{n}}$ is $\displaystyle { }^{\mathrm{n}} \mathrm{C}_{23}$, is :
Official answer
(2)
$\displaystyle 38$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.