Mathematics · 2020
JEE Main · 9 January 2020, Shift 1 · Q57
The product 2^(1/4) · 4^(1/16) · 8^(1/48) · 16^(1/128) · … to ∞ is equal to:
The product
$$2^{\frac{1}{4}} \cdot 4^{\frac{1}{16}} \cdot 8^{\frac{1}{48}} \cdot 16^{\frac{1}{128}} \cdot \ldots \text { to } \infty
$$
is equal to:
Official answer
(2)
$\displaystyle 2^{\frac{1}{2}}$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.