Mathematics · 2026
JEE Main · 22 January 2026, Shift 1 · Q12
The number of solutions of tan^-1 4 x+ tan^-1 6 x=(π)/6, where -1/(2 √ 6)<x<1/(2 √ 6), is equal to
The number of solutions of $\displaystyle \tan ^{-1} 4 x+\tan ^{-1} 6 x=\frac{\pi}{6}$, where $\displaystyle -\frac{1}{2 \sqrt{6}}<x<\frac{1}{2 \sqrt{6}}$, is equal to
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 1$
More from Inverse Trigonometric Functions
- If (π)/4+Σ_p=1^11 tan^-1((2^p-1)/(1+2^2 p-1))=α, then tan α is equal to ____.2026
- Let α=3 sin^-1(6/11) and β=3 cos^-1(4/9), where inverse trigonometric functions take only the principal values. Given below are two statements:…2026
- Let 0<α<1, β=1/(3 α) and tan^-1(1-α)+ tan^-1(1-β)=(π)/4. Then 6(α+β) is equal to:2026
- Let [·] denote the greatest integer function. If the domain of the function f(x)= sin^-1((x+[x])/3) is [α, β), then α^2+β^2 is equal to:2026
- Let [·] denote the greatest integer function. If the domain of the function f(x)= cos^-1((4 x+2[x])/3) is [α, β], then 12(α+β) is equal to:2026
- If sin ( tan^-1(x √2))= cot ( sin^-1 √(1-x^2)), x ∈(0,1), then the value of x is:2026
JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.