Mathematics · 2026
JEE Main · 6 April 2026, Shift 2 · Q13
If sin ( tan^-1(x √ 2 ))= cot ( sin^-1 √(1-x^2)), x ∈(0,1), then the value of x is:
If $\displaystyle \sin \left(\tan ^{-1}(x \sqrt{2})\right)=\cot \left(\sin ^{-1} \sqrt{1-x^2}\right), x \in(0,1)$, then the value of $\displaystyle x$ is :
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle \frac{1}{2}$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.