Mathematics · 2021
JEE Main · 18 March 2021, Shift 1 · Q90
The number of solutions of the equation | cot x|= cot x+1/(sin x) in the interval [0,2 π] is \ \ \ \.
The number of solutions of the equation $\displaystyle |\cot x|=\cot x+\frac{1}{\sin x}$ in the interval $\displaystyle [0,2 \pi]$ is
\_\_\_\_.
Official answer
1
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