Mathematics · 2018
JEE Main · 15 April 2018, Shift 2 · Q88
The number of solutions of sin 3 x= cos 2 x, in the interval ((π)/2, π) is:
The number of solutions of $\displaystyle \sin 3 x=\cos 2 x$, in the interval $\displaystyle \left(\frac{\pi}{2}, \pi\right)$ is :
Official answer
(1)
$\displaystyle 1$
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JEE Main 2018 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.