Mathematics · 2021
JEE Main · 16 March 2021, Shift 1 · Q68
The number of roots of the equation, (81)^sin^2 x+(81)^cos^2 x=30 in the interval [0, π] is equal to:
The number of roots of the equation,
$$(81)^{\sin ^2 x}+(81)^{\cos ^2 x}=30
$$
in the interval $\displaystyle [0, \pi]$ is equal to :
Official answer
(3)
$\displaystyle 4$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.