Mathematics · 2020
JEE Main · 7 January 2020, Shift 2 · Q54
The number of ordered pairs ( r, k ) for which 6 ·^35 C_r =( k^2-3) ·^36 C_r +1, where k is an integer, is:
The number of ordered pairs $\displaystyle (\mathrm{r}, \mathrm{k})$ for which $\displaystyle 6 \cdot{ }^{35} \mathrm{C}_{\mathrm{r}}=\left(\mathrm{k}^2-3\right) \cdot{ }^{36} \mathrm{C}_{\mathrm{r}+1}$, where k is an integer, is :
Official answer
(4)
$\displaystyle 4$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.