Offline paper
Mathematics · 2015
JEE Main 2015 · 2015-04-04 Offline · Q72
The normal to the curve, x^2+2 x y-3 y^2=0, at (1,1):
The normal to the curve, $\displaystyle x^2+2 x y-3 y^2=0$, at $\displaystyle (1,1)$ :
Official answer
(4)
meets the curve again in the fourth quadrant.
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JEE Main 2015 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.