Mathematics · 2020
JEE Main · 4 September 2020, Shift 2 · Q60
The minimum value of 2^sin x+2^cos x is:
The minimum value of $\displaystyle 2^{\sin x}+2^{\cos x}$ is :
Official answer
(1)
$\displaystyle 2^{1-\frac{1}{\sqrt{2}}}$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.