Mathematics · 2021
JEE Main · 24 February 2021, Shift 1 · Q86
The minimum value of α for which the equation 4/(sin x)+1/(1- sin x)=α has at least one solution in (0, (π)/2) is \ \ \ \.
The minimum value of $\displaystyle \alpha$ for which the equation $\displaystyle \frac{4}{\sin x}+\frac{1}{1-\sin x}=\alpha$ has at least one solution in $\displaystyle \left(0, \frac{\pi}{2}\right)$ is \_\_\_\_.
Official answer
9
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.