Mathematics · 2021
JEE Main · 26 February 2021, Shift 1 · Q71
The maximum value of the term independent of ' t ' in the expansion of ( t x^(1/5)+((1-x)^(1/10))/t)^10 where x ∈(0,1) is:
The maximum value of the term independent of ' $\displaystyle t$ ' in the expansion of $\displaystyle \left(\mathrm{t} x^{\frac{1}{5}}+\frac{(1-x)^{\frac{1}{10}}}{\mathrm{t}}\right)^{10}$ where $\displaystyle x \in(0,1)$ is :
Official answer
(2)
$\displaystyle \frac{2.10!}{3 \sqrt{3}(5!)^2}$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.