Mathematics · 2021
JEE Main · 25 July 2021, Shift 2 · Q62
The lowest integer which is greater than (1+1/(10^100))^10^100 is \ \ \ \.
The lowest integer which is greater than $\displaystyle \left(1+\frac{1}{10^{100}}\right)^{10^{100}}$ is \_\_\_\_.
Official answer
(3)
$\displaystyle 3$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.