Mathematics · 2020
JEE Main · 8 January 2020, Shift 2 · Q60
The length of the perpendicular from the origin, on the normal to the curve, x^2+2 x y-3 y^2=0 at the point (2,2) is:
The length of the perpendicular from the origin, on the normal to the curve, $\displaystyle x^2+2 x y-3 y^2=0$ at the point $\displaystyle (2,2)$ is :
Official answer
(3)
$\displaystyle 2 \sqrt{2}$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.