Mathematics · 2024
JEE Main · 6 April 2024, Shift 2 · Q27
The length of the latus rectum and directrices of a hyperbola with eccentricity e are 9 and x= ± 4/(√ 3), respectively. Let the line y-√ 3 x+√ 3 =0…
The length of the latus rectum and directrices of a hyperbola with eccentricity e are $\displaystyle 9$ and $\displaystyle x= \pm \frac{4}{\sqrt{3}}$, respectively. Let the line $\displaystyle y-\sqrt{3} x+\sqrt{3}=0$ touch this hyperbola at $\displaystyle \left(x_0, y_0\right)$. If $\displaystyle m$ is the product of the focal distances of the point $\displaystyle \left(x_0, y_0\right)$, then $\displaystyle 4 \mathrm{e}^2+\mathrm{m}$ is equal to $\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
No correct option: NTA dropped this question in its final answer key.
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.