Mathematics · 2025
JEE Main · 2 April 2025, Shift 1 · Q10
Let one focus of the hyperbola H: x^2/(a^2)-y^2/(b^2)=1 be at (√ 10, 0) and the corresponding directrix be x=9/(√ 10). If e and l respectively are…
Let one focus of the hyperbola H : $\displaystyle \frac{x^2}{\mathrm{a}^2}-\frac{y^2}{\mathrm{~b}^2}=1$ be at $\displaystyle (\sqrt{10}, 0)$ and the corresponding directrix be $\displaystyle x=\frac{9}{\sqrt{10}}$. If $\displaystyle e$ and $\displaystyle l$ respectively are the eccentricity and the length of the latus rectum of H, then $\displaystyle 9\left(e^2+l\right)$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 16$
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