Mathematics · 2026
JEE Main · 23 January 2026, Shift 2 · Q18
The least value of ( cos^2 θ-6 sin θ cos θ+3 sin^2 θ+2) is
The least value of $\displaystyle \left(\cos ^2 \theta-6 \sin \theta \cos \theta+3 \sin ^2 \theta+2\right)$ is
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 4-\sqrt{10}$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.