Mathematics · 2021
JEE Main · 31 August 2021, Shift 1 · Q70
The integral ∫ 1/(√[4]((x-1)^3(x+2)^5)) d x is equal to: (where C is a constant of integration)
The integral $\displaystyle \int \frac{1}{\sqrt[4]{(x-1)^3(x+2)^5}} \mathrm{~d} x$ is equal to :
(where $\displaystyle C$ is a constant of integration)
Official answer
(1)
$\displaystyle \frac{4}{3}\left(\frac{x-1}{x+2}\right)^{\frac{1}{4}}+C$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.