Mathematics · 2019
JEE Main · 10 April 2019, Shift 2 · Q75
The integral ∫_π / 6^π / 3 sec^2 / 3 x cosec^4 / 3 x d x is equal to:
The integral $\displaystyle \int_{\pi / 6}^{\pi / 3} \sec ^{2 / 3} x \operatorname{cosec}^{4 / 3} x \mathrm{~d} x$ is
equal to :
Official answer
(4)
$\displaystyle 3^{7 / 6}-3^{5 / 6}$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.