Mathematics · 2020
JEE Main · 6 September 2020, Shift 2 · Q61
The integral ∫_1^2 e^x · x^x(2+ log_e x) d x equals:
The integral $\displaystyle \int_1^2 \mathrm{e}^x \cdot x^x\left(2+\log _{\mathrm{e}} x\right) d x$
equals :
Official answer
(3)
$\displaystyle e(4 e-1)$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.