Mathematics · 2020
JEE Main · 4 September 2020, Shift 2 · Q61
The integral ∫_π / 6^π / 3 tan^3 x · sin^2 3 x(2 sec^2 x · sin^2 3 x+3 tan x · sin 6 x) d x is equal to:
The integral
$$\int_{\pi / 6}^{\pi / 3} \tan ^3 x \cdot \sin ^2 3 x\left(2 \sec ^2 x \cdot \sin ^2 3 x+3 \tan x \cdot \sin 6 x\right) \mathrm{d} x \text { is }
$$
equal to :
Official answer
(4)
$\displaystyle -\frac{1}{18}$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.