Mathematics · 2014
JEE Main · 19 April 2014, Shift 1 · Q80
The equation of the circle described on the chord 3 x+y+5=0 of the circle x^2+y^2=16 as diameter is:
The equation of the circle described on the chord $\displaystyle 3 x+y+5=0$ of the circle $\displaystyle x^2+y^2=16$ as diameter is :
Official answer
(1)
$\displaystyle x^2+y^2+3 x+y-11=0$
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JEE Main 2014 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.